Gas Stoichiometry from Reaction Volumes
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Solving a gas stoichiometry problem means converting a given gas volume to moles with the ideal gas law when conditions are unmatched, applying the balanced equation's mole ratio, then converting back to volume under the target conditions, or using the volume ratio directly when conditions already match.
Burning propane, C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O, requires O₂ in a 1:5 ratio at matching temperature and pressure, so 2.7 L of propane needs 5 × 2.7 = 13.5 L of O₂ measured under those same conditions, and produces 3 × 2.7 = 8.1 L of CO₂ under the same conditions as well.
Applying the equation's mole-ratio numbers directly to volumes measured at two different temperatures or pressures skips the mole conversion this shortcut depends on.
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