Descriptive, Organic, and Nuclear Chemistry
Part 3 of 5: Transition Metals and Coordination Compounds. This unit runs past the 40-minute ceiling, so it ships in 5 lectures.
The narration between entries paraphrases; it never reads an entry aloud before the entry plays. Every entry in this lecture plays exactly as it does on its own page — same file, same speed, nothing laid over it.
What you can do after this
- Say what defines a transition metal, and why group 12 falls outside the strict definition
- Determine a ligand's denticity by counting the right thing
- Name a coordination compound and find the metal's oxidation state from its charge
- Say what decides whether a complex is high-spin or low-spin
- Say why some complexes are coloured and others are not
What it covers
15 entries in 5 topics. Each number links to that entry on its own.
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1. What a transition metal is
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2. Coordination compounds
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3. Two kinds of isomerism
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4. Crystal field splitting
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5. Colour, and the capstone
Check yourself
What defines a transition metal, and why does group 12 fall outside it?
A transition metal is an element that has, or readily forms ions with, a partially filled set of d orbitals. Among the d-block that holds for groups 3 through 11 — iron, for instance, whose configuration leaves its d orbitals partly filled. The definition is about orbital occupancy rather than position on the table, which is what puts group 12 outside it. Zinc, cadmium and mercury complete their d orbitals entirely, and when they ionise they lose only s electrons, so neither the atom nor its common ions ever have a partially filled d set. By the strict definition they are representative metals, despite sitting in the middle of the table and being grouped informally with the transition metals in ordinary usage. This is the same shape of point Part 1 made about classification by orbital filling: where the table's visual layout and the actual electron configuration disagree, the configuration is what the definition follows.
How do you determine a ligand's denticity?
By counting donor atoms — the atoms that actually donate an electron pair to the metal — and nothing else. A monodentate ligand bonds through a single donor atom; a polydentate ligand, also called a chelating ligand, bonds through two or more at once. Chloride has one donor atom and is monodentate. Ethylenediamine has two donor nitrogens and is bidentate, gripping the metal at two points. The mistake worth guarding against is counting atoms in the ligand rather than donor atoms in the ligand. Ligands vary enormously in size, and a large organic molecule with a single coordinating atom is monodentate no matter how many carbons and hydrogens it carries. Size and denticity are unrelated: what matters is how many points of attachment the ligand makes to the metal centre, because that is what determines how it occupies the coordination sphere.
How do you name a coordination compound and get the metal's oxidation state?
Name the ligands first, alphabetically, with multiplying prefixes for repeats; then the metal; then the metal's oxidation state as a Roman numeral in parentheses. If the complex ion is an anion, the metal's name takes the suffix -ate. The oxidation state is not looked up — it is worked out by balancing charge within the coordination sphere. Take [Cr(H₂O)₄Cl₂]Cl. The sphere must carry 1+ to balance the outer chloride. Inside the brackets are four neutral water ligands and two chloride ligands at 1− each, so +1 = −2 + x, giving chromium 3+, and the name is tetraaquadichlorochromium(III) chloride. The error the book flags is including the counter-ion in that balance. Ligands outside the brackets are not bonded to the metal and take no part in the coordination sphere's charge; counting them produces an oxidation state inconsistent with the complex's actual charge.
What decides whether a complex is high-spin or low-spin?
The size of the crystal field splitting compared with the energy cost of pairing two electrons in one orbital — and the splitting size is set by the ligand. When ligands surround a metal ion octahedrally, the d orbitals pointing directly at them rise above those pointing between them, separating one energy level into two. If that gap is small, an electron finds it cheaper to occupy an empty upper orbital than to pair up in a lower one, so electrons spread out singly and the complex is high-spin with the maximum number of unpaired electrons. If the gap is large, pairing costs less than the promotion, so electrons fill the lower orbitals in pairs and the complex is low-spin. The spectrochemical series ranks ligands by the splitting they produce, and that ranking follows the ligand's own electronic character rather than the metal's identity. The consequence is the one the book insists on: spin state is not a property of the metal. Iron(II) is high-spin with water and low-spin with cyanide — same ion, opposite answer, because the ligand changed.
Why are some complexes coloured and others not?
Because colour here comes from an electron absorbing visible light to jump between the two split d levels, and that requires both a gap of roughly the right size and electrons able to make the jump. Crystal field splitting separates the d orbitals by an energy that happens to fall in the visible range, so a complex absorbs the wavelengths matching its own gap and transmits the rest — and the colour seen is complementary to the colour absorbed, which is why a complex absorbing mostly red light appears green. Where that fails is at the two ends of the d-block. A metal ion with an empty d subshell, like Sc³⁺, has no electron available to promote; one with a completely filled d subshell, like Zn²⁺, has no vacancy to promote an electron into. Either way there is no d–d transition to make, no visible light is absorbed, and the complex is colourless — which is a useful check, since it ties the colour directly back to the partially filled d set that defines a transition metal in the first place.
Lecture transcript
The narration as recorded, in order. Where an entry plays, the transcript links to it rather than reprinting it — the entry plays from its own file, unaltered, and says the same thing on its own page.
This is Unit Twelve of Chemistry, Part Three: transition metals and coordination compounds. Parts One and Two read the periodic table's two edges — the reactive metals and the nonmetals — and closed on a capstone predicting an element's chemistry from position alone. This part turns to the block in the middle, where that approach stops being sufficient. Transition metals are defined by partially filled d orbitals, and the consequences of those orbitals are what this part is about: multiple oxidation states rather than one, compounds built by accepting electron pairs from surrounding molecules, more kinds of isomerism than a simple formula can distinguish, and colour. The single idea holding the second half together is that ligands change the energies of a metal's d orbitals, and how much they change them decides both how the electrons arrange themselves and what colour the compound is. By the end you will be able to say what defines a transition metal and why group twelve falls outside the strict definition; determine a ligand's denticity by counting the right thing; name a coordination compound and find the metal's oxidation state from its charge; say what decides whether a complex is high-spin or low-spin; and say why some complexes are coloured and others are not.
Three entries. A definition that rests on orbital occupancy rather than position, and which excludes one group people usually include. Then two trends about oxidation states that look similar and answer different questions — one runs across a period, the other down a group.
Partially filled d.
Chem 2372 Transition Metals Defined by Partially Filled d Orbitals
A transition metal has, or readily forms ions with, a partially filled set of d orbitals — which among the d-block covers groups three through eleven. Iron qualifies: its configuration leaves the d orbitals partly filled. Group twelve does not, on the strict definition. It fills its d orbitals completely and loses only s electrons when it ionises, which places it with the representative metals despite being grouped informally with the rest.
Most in the middle.
Chem 2375 Multiple Oxidation States Peak Mid-First-Series
Across the first transition series the number of available oxidation states rises toward the middle and falls off at both ends, because later members hold their d electrons more stably. Manganese, near the middle, runs from two plus through seven plus — far more than scandium or copper at the ends. Having one fixed oxidation state is not what transition metal means; this variability is the group's defining signature.
Further down, higher up.
Chem 2378 Heavier d-Block Series Favor Higher Oxidation States
Second and third series elements are more stable in higher oxidation states than their first-series counterparts, because larger atomic radii make the outer electrons easier to remove. Molybdenum and tungsten sit below chromium and are largely limited to six plus in solution, where chromium favours the more stable three plus. This is a trend down a group, and the previous entry's was a trend across a period — they answer different questions.
Four entries building the central object of this part. A coordination compound is a Lewis acid–base adduct, which is Unit Ten's framework applied to a metal ion: the metal accepts electron pairs, the surrounding molecules donate them. Then what the number of those donors decides about shape, how to count them properly, and the naming procedure — which is worth more than it looks, because working out the name is how you work out the metal's oxidation state.
Donated, not shared equally.
Chem 2381 Coordination Compounds as Lewis Acid-Base Adducts
A coordination compound forms when a central metal ion acts as a Lewis acid and accepts electron pairs donated by ligands acting as Lewis bases. In the hexaamminecobalt ion, six ammonia molecules each donate a nitrogen lone pair to the cobalt centre. These are genuine bonds — the term coordinate covalent describes where the electrons came from originally, not any weakness in the bond itself.
Count the donors.
Chem 2384 Coordination Number Sets Complex Geometry
A complex's coordination number is the count of donor atoms bonded to the central metal, and it sets the geometry: two gives linear, four gives tetrahedral or square planar, six gives octahedral. The diamminesilver ion is linear; the hexaaquacobalt ion is octahedral. Unlike VSEPR, nonbonding d electrons do not distort the shape here — coordination number alone predicts how the donor atoms arrange.
One donor, or several.
Chem 2387 Monodentate vs. Polydentate Ligands
A monodentate ligand bonds through a single donor atom; a polydentate, or chelating, ligand bonds through two or more donor atoms at once. Chloride is monodentate. Ethylenediamine has two donor nitrogens and is bidentate. What settles denticity is the number of donor atoms and not the size of the molecule — a large ligand with one donor atom is monodentate however many atoms it contains.
The name gives the oxidation state.
Chem 2390 Naming a Coordination Compound
Name the ligands alphabetically with multiplying prefixes, then the metal, then a Roman numeral for its oxidation state — and add the suffix -ate to the metal's name if the complex is an anion. The oxidation state comes from balancing: the ligand charges inside the brackets against the coordination sphere's overall charge. In tetraaquadichlorochromium chloride, the sphere carries one plus, four waters are neutral and two chlorides are one minus each, so chromium is three plus. The chloride sitting outside the brackets plays no part in that balance — including it gives an oxidation state the complex's charge will not support.
Two entries on complexes that share a formula and are nonetheless different compounds. The first kind you can tell apart by looking — the isomers differ in colour and polarity. The second kind you cannot: the two forms are nearly identical in every ordinary physical property and differ only in how they interact with polarised light and with other handed molecules.
Adjacent, or opposite.
Chem 2394 Geometric Isomerism in Complexes
Geometric isomers carry the same ligands on the same metal and differ in how those ligands are arranged: cis places like ligands adjacent, trans places them opposite. A tetraamminedichlorocobalt ion has its two chlorides adjacent in the cis form and across the octahedron in the trans. These are different compounds with different properties — different colour, different polarity — not one compound drawn two ways.
Left hand, right hand.
Chem 2397 Optical Isomerism (Enantiomers)
Optical isomers, or enantiomers, are nonsuperimposable mirror images — related as a left hand is to a right hand. The tris-ethylenediamine cobalt ion exists as such a pair. Unlike geometric isomers they share nearly identical melting point, boiling point and solubility, so ordinary measurements will not separate them; what distinguishes them is their interaction with polarised light and with other chiral molecules.
Four entries, and this is the mechanism the second half of the part rests on. When ligands approach a metal ion, they raise the energies of the d orbitals pointing at them more than the ones pointing between them, so a set that was all one energy separates into two levels. How wide that separation is depends on the ligand — and the width decides how the electrons distribute themselves. The registered twin here names the two possible outcomes.
Pointing at, or between.
Chem 2400 Crystal Field Splitting in an Octahedral Complex
In an octahedral complex, the ligands' electron pairs raise the two d orbitals that point directly at them above the three that point between them — the crystal field splitting. Iron's five equal-energy d orbitals separate into a higher pair and a lower trio once ligands coordinate around it. The orbitals do not merge or disappear: what changes is their energies, not how many there are.
Which ligand, and how much.
Chem 2403 The Spectrochemical Series: Weak- vs. Strong-Field Ligands
The spectrochemical series ranks ligands by how large a crystal field splitting they produce, from weak-field ligands that separate the levels slightly to strong-field ligands that separate them widely. Cyanide is strong-field and produces a much larger splitting than iodide, which is weak-field. A ligand's place in that ranking follows from its own electronic character, not from the identity or charge of the metal it happens to bond to.
Spread out first.
Chem 2406 Twin: The High-Spin Complex
A high-spin complex forms when the splitting is small enough that electrons occupy every d orbital singly before any of them pair up, which maximises the number of unpaired electrons. The hexaaquairon two-plus ion, with water as a weak-field ligand, is high-spin and carries four unpaired electrons out of six. High-spin is not a description of the metal — the same ion is high-spin with one ligand and low-spin with another, because the ligand sets the splitting.
Pair up instead.
Chem 2409 Twin: The Low-Spin Complex
A low-spin complex forms when the splitting is large enough that pairing two electrons in a lower orbital costs less energy than promoting one to the upper level — which minimises unpaired electrons. The hexacyanoferrate two-minus ion, with strong-field cyanide, is low-spin and carries none unpaired out of six. The comparison that shows what is varying is the same metal with a different ligand, not a different metal.
Two entries closing the part. Transition metal complexes are the coloured compounds of inorganic chemistry, and the splitting from the previous topic is why — the gap between those two d levels is exactly the sort of energy that visible light carries. Then the capstone, which takes one complex and answers four separate questions about it from a single fact: which ligand it has.
A jump the size of visible light.
Chem 2412 Complex Color from d-d Electron Transitions
A complex is coloured when an electron absorbs visible light to jump between d orbitals, and the colour you see is complementary to the light absorbed — a complex absorbing mostly red appears green, as many chromium three-plus complexes do. A metal ion with an empty or a completely filled d subshell has no such transition available, so scandium three-plus and zinc two-plus complexes are colourless.
Four answers, one ligand.
Chem 2417 Capstone: Full Analysis of a Coordination Complex
Hexacyanoferrate three-minus. Balancing charge, six cyanides at one minus each against a sphere at three minus makes iron three plus, and because the complex is an anion the name takes the -ate ending. No geometric isomerism is possible, because all six ligands are identical and cis-trans needs at least two different ligand types. Cyanide is strong-field, so a large splitting is predicted; iron three plus has five d electrons, and a large splitting favours pairing them low rather than promoting one, predicting a low-spin complex with one unpaired electron. That same large gap shifts absorption toward higher-energy light. One honest qualification: this particular ion's intense colour also involves charge-transfer absorption beyond the simple d–d picture, so colour follows the splitting direction more loosely than the other three answers do. And none of this makes iron three plus low-spin in general — swapping cyanide for fluoride around the same centre would predict high-spin.
Five things to carry out of this part. A transition metal is one with, or readily forming ions with, a partially filled set of d orbitals — groups three through eleven of the d-block. Group twelve falls outside the strict definition, because it fills its d orbitals completely and loses only s electrons on ionising, whatever the informal grouping suggests. A ligand's denticity is set by how many donor atoms it bonds through, not by how large the molecule is: chloride is monodentate, ethylenediamine with two donor nitrogens is bidentate, and a large ligand with a single donor atom is still monodentate. Naming a coordination compound gives you the metal's oxidation state as a by-product, because you get it by balancing the charges of the ligands inside the brackets against the coordination sphere's overall charge — and anything written outside those brackets plays no part in that balance. Whether a complex is high-spin or low-spin is decided by the size of the crystal field splitting relative to the cost of pairing electrons, and the splitting size is set by the ligand rather than the metal: a small splitting spreads electrons out singly and gives high spin, a large one pairs them low and gives low spin, and the same metal ion gives either answer depending on what surrounds it. And a complex is coloured when an electron can absorb visible light to jump between those split d levels, which is why a metal ion with an empty or a full d subshell has no transition available and its complexes are colourless. Part Four takes up organic chemistry.
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